x^(3)+3x^(2)-5x+4" by "x-2

If A, B, C are the remainders of x^(3) - 3x^(2) - x + 5, 3x^(4) - x^(3) + 2x^(2) - 2x - 4, 2x^(5) - 3x^(4) + 5x^(3) - 7x^(2) + 3x - 4 when divided by x + 1, x + 2, x - 2 respectively then the ascending order of A, B ,C is

Using remainder theorem, find the remainder when p(x) = x^(3)+ 3x^(2) - 5x+4 is divided by (x-2).

Subtract : x^(3) + 3x^(2) - 5x + 4 from 3x^(3) - x^(2) + 2x - 4

Divide 3x^(4) - 5x^(3)+4x^(2)+3x-5 by x^(2) - 3 and verify the division algorithm.

From the sum of 6x^(4) - 3x^(3) + 7x^(2) - 5x + 1 and -3x^(4) + 5x^(3) - 9x^(2) + 7x - 2 subtract 2x^(4) - 5x^(3) + 2x^(2) - 6x - 8

Divide 2x^5 -3x^4 +5x^3 -7x^2 +3x -4 by x-2.

Divide 2x^5 -3x^4 +5x^3 -7x^2 +3x -4 by x-2.

Multiply (2x^(3) - 5x^(2) - x + 7) by (3 - 2x + 4x^(2))