In the figure (i) given below, O is the centre of the circle. AB and CD are the chords of the circle. OM is perpendicular to AB and ON is perpendicular to CD. AB=24 cm OM=5 cm, ON=12 cm. Find the, (i) radius of the circle (ii) length of chord CD (ii) In the figure (ii) given below, CD is diameter which meets the chord AB at E such that AE = BE = 4 cm.If CE = 3 cm, find the radius of the circle.

Explanation

In `triangle OAM`

`OA^2=OM^2+AM^2`

`r^2=5^2+12^2`

`r^2=169`

r=13

In`triangleONC`

`OC^2=ON^2+NC^2`

`NC^2=169-144`

...