The e.m.f. of a cell is 6 volt. When 2 ampere current is drawn from it then th e potential difference across its terminal remains 3 volt. Its internal resistance.

On increasing the current drawn from a cell, the potential difference across its terminals is lowered why?

The emf of a cell is 2 V. When the terminals of the cell is connected to a resistance 4Omega . The potential difference across the terminals, if internal resistance of cell is 1Omega is

The internal resistance of cell is 0.1 Omega and its emf is 2V. When a current of 2A is being drawn from it, the potential difference across its terminals will be :

E.M.F. of electrical cell is 2 volt. A 10Omega resistance is joined at its two ends then potential difference in measured 1.6 volt. Find out the internal resistance and lost volt.

In a network as shown in the figure , the potential difference across the resistance 2 R is (the cell has emf E - volt and no internal resistance )

EMF of an electrical cell is 2 volt. A 10 Omega resistance is joined at its two ends then potential difference is measured 1.6 volt. Find out the internal resistance and lost volt.

The potential difference in open circuit for a cell is 2.2 volts. When a 4 ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be

Choose correct alternative. emf of a cell is 2.2 volt. When resistance R = 5 Omega is connected in series potential drop across the cell becomes 1.8 volt. Value of internal resistance of the cell is