The oscillating frequency of a cyclotron is `10 MHz`. If the radius of its Dees is `0.5 m`, the kinetic energy of a proton which is accelerated by the cyclotron is

A proton of charge e and mass "m" is accelerated in a cyclotron having an oscillator frequency f.The magnetic induction of the field in the cyclotron is B.If the radius of the D's is r ,the kinetic energy of the protons that come out of the cyclotron is

In a cyclotron the frequency of alternating current is 12 MHz and the radii of its dee is 0.53m . What is the kinetic energy of the proton beam produced by the cyclotron ? Given mass of proton =1.67xx10^(-27) kg and charge =+1.6xx10^(-19)C .

If the radius of the dees of cyclotron is r then the kinetic energy of a proton of mass m accelerated by the cycloton at an oscillating frequency v is

A cyclotron.s oscillator frequency is 10 MHz and the operating magnetic field is 0.66 T. If the radius of its dees is 60 cm, then the kinetic energy of the proton beam produced by the accelerator is

A cycolotron's oscillator frequency is 10 MHz and the operating magnetic is 0.66 T . If the radius of its dees is 60 cm, then the kinetic energy of the proton beam produced by the accelerator is

A cyclotron oscillator frequency is 10MHz . What should be the operating magnetic field for accelerating protons? If the radius of its dees is 60cm , what is the kinetic energy of the proton beam produced by the acceleration in MeV ? (e=1*6xx10^(-19)C, m_p=1*67xx10^(-27)kg, 1MeV=1*6xx10^(-13)J)

A cyclotron is operated at an oscillator frequency of 12 MHz and has a dee radius R 50 cm. What is the magnitude of the magnetic field needed for a proton to be accelerated in the cyclotron?

A cyclotron is operated at an oscillator frequency of 12 MHz and has a dee radius R 50 cm. What is the magnitude of the magnetic field needed for a proton to be accelerated in the cyclotron?