Home
Class 12
PHYSICS
The binding energy expressed in MeV is g...

The binding energy expressed in MeV is given for the following nulcear reactions
`_(2)He^(3) + _(0)n^(1) to _(2)He^(4) + 20 MeV`
`_(2)He^(4) + _(0)n^(1) to _(2)He^(5) + 0.9 meV`
Which of the following conclusion is correct ?

Promotional Banner

Similar Questions

Explore conceptually related problems

The binding energy expressed in MeV is given for the following nuclear reactions _(2)He^(3) + _(0)n^(1) to _(2)He^(4) + 20 MeV _(2)He^(4) + _(0)n^(1) to _(2)He^(5) + 0.9 meV Which of the following conclusion is correct ?

Calculate the energy released per nucleon of the reactant, in the thermonuclear reaction 3_(1)H^(2) to _(2)He^(4)to_(2)He^(4)+_(1)H^(1)+_(0)n^(1)+21.6 MeV

Calculate the energy in the given fusion reaction. ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) +n Given, B.E. of ""_(1)H^(2) = 2.23 MeV and B.E. of ""_(2)He^(3) = 7.73 MeV.

Calculate the energy released in joules and MeV in the following nuclear reaction: ._(1)H^(2) + ._(1)H^(2) rarr ._(2)He^(3) + ._(0)n^(1) Assume that the masses of ._(1)H^(2) , ._(2)He^(3) , and neutron (n) , respectively, are 2.40, 3.0160, and 1.0087 in amu.

Calculate the energy released in joules and MeV in the following nuclear reaction: ._(1)H^(2) + ._(1)H^(2) rarr ._(2)He^(3) + ._(0)n^(1) Assume that the masses of ._(1)H^(2) , ._(2)He^(3) , and neutron (n) , respectively, are 2.40, 3.0160, and 1.0087 in amu.

Calculate the energy released in joules and MeV in the following nuclear reaction : ._(1)^(2) H+_(1)^(2) rarr _(2)^(3)He + _(0)^(1)n Assume that the masses of ._(1)^(2)H, _(2)^(3)He and neutron (n) respectively are 2.020, 3.0160 and 1.0087 in amu.

Calcualte the energy released (in joule and MeV ) in the follwing nulcear reaction: ._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n Assume that the masses of ._(1)^(2)H, ._(2)^(3)He and neutron (n) are 2.0141,3.0160 and 1.0087 respectively in amu.

Calculate the energy in fusion reaction: ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) + ""_(0)n^(1) , where B.E. Of ""_(1)H^(2) = 2.23 MeV and ""_(2)He^(3) = 7.73 MeV.

Calculate the loss in mass during the change: ._(3)Li^(7) + ._(1)He^(1) rarr 2 ._(2)He^(4) + 17.25 MeV