" If "3tan theta=4," culuate "(3sin theta+2cos theta)/(3sin theta-2cos theta)

If 3 tan theta =4 , "evaluate "(3sin theta + 2 cos theta)/(3 sin theta - 2 cos theta ).

If 4tan theta=3, evaluate (4sin theta-cos theta+1)/(sin theta+cos theta-1)

If 4tan theta=3, the value of ((4sin theta-2cos theta)/(4sin theta+2cos theta)) is:

If 4 tan theta = 3, evaluate ((4 sin theta -2 cos theta+3)/(4 sin theta + 2cos theta-5))

If tan theta = 4/3 ,then the value of (3 sin theta + 2cos theta)/(3 sin theta - 2 cos theta) is

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

If 4 tan theta =3 , evaluate ((4 sin theta - 2cos theta +3)/(4 sin theta +2 cos theta -5))

If tan theta=1 then (8sin theta +5 cos theta)/(sin^3theta-2cos^3theta+7cos theta)=

If tan theta = (5)/(4) , then the value of ((3 sin theta + 4 cos theta)/(3 sin theta - 4 cos theta))^(2) is