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In the visible region of the spectrum th...

In the visible region of the spectrum the rotation of the place of polarization is given by `theta=a+(b)/(lambda^2)`. The optical rotation produced by a particular material is found to be `30^@` per mm at `lambda=5000Å` and `50^@` per mm at `lambda=4000Å`. The value of constant a will be

A

`+(50^(@))/(9)` per mm

B

`-(50^(@))/(9)` per mm

C

`+(9^(@))/(50)` per mm

D

`-(9^(@))/(50)` per mm

Text Solution

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The correct Answer is:
B
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ERRORLESS -WAVE OPTICS-SET
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