In the circuit shown, `C_(1)=C_(2)=2 muF`. Capacitor `C_(1)` is charged to `50 V` and `C_(1)` is charge to `20 V`. After charging they are connected as shown. When `S_(1), S_(2)`, and `S_(3)`, are clsosed,
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In the circuit shown in figure C_(1)= 1mu F and C_(2) = 2 mu F . The capacitor C_(1) is charged to 100 V and the capacitor C_(2) is charged to 20 V . After charging then are connected as shown. When the switches S_(1),S_(2) and S_(3) are closed, the charged flowing through S_(1) is .

In the circuit shown in figure C_(1) =C_(2) = 2muF . Then charge stored in

In the circuit shown in figure C_(1) = 2 C_(2) . Capacitance C_(1) is charged to a potential of V. The current in the circuit just after the switch S is closed is

In the circuit shown in figure C_(1) = 2 C_(2) . Capacitance C_(1) is charged to a potential of V. The current in the circuit just after the switch S is closed is

In the circuit shown in fig. C_1 = 2C_2 Initially, capacitor C_1 is charged to a potential of V. The current in the circuit just after the switch S is closed is

In the circuit shown, the capacitor C_1 is initially charged with charge q_0 . The switch S is closed at time t = 0 . The charge on C_2 after time t is

In the circuit shown, the capacitor C_1 is initially charged with charge q_0 . The switch S is closed at time t = 0 . The charge on C_2 after time t is

Consider the circuit shown where C_(1) = 6 mu F, C_(2) = 3 mu F and V=20 V. Capacitor C_(1) is first charged by closing the switch S_(1). Switch S_(1) is then opened, and the charged capacitor is connected to the uncharged capacitor C_(2) by closing S_(2).