In an equilateral triangle `A B C` the side `B C` is trisected at `D` . Prove that `9\ A D^2=7\ A B^2`

Solve the following sub question : In an equilateral triangle ABC, the side BC is trisected at D. prove that 9 AD^(2) = 7 AB^(2)

In an equilateral triangle ABC,the side BC is trisected at D.Prove that: 9AD^2=7AB^2 .

In an equilateral triangle ABC the side BC is trisected at D. Prove that 9AD^(2)=7AB^(2)

In an equilateral triangle A B C if A D_|_B C , then

In an equilateral DeltaABC, the side BC is trisected at D. Prove that 9AD^(2)=7AB^(2). (Hint : AEbotBC )

In an equilateral triangle ABC, D is a point on side BC such that B D=1/3B C . Prove that 9A D^2=7A B^2 .

A point D is on the side B C of an equilateral triangle A B C such that D C=1/4\ B C . Prove that A D^2=13\ C D^2 .

The perpendicular A D on the base B C of a triangle A B C intersects B C at D so that D B=3C D . Prove that 2\ A B^2=2\ A C^2+B C^2 .

In an equilateral triangle A B C , if A D_|_B C , then (a) 2\ A B^2=3\ A D^2 (b) 4\ A B^2=3\ A D^2 (c) 3\ A B^2=4\ A D^2 (d) 3\ A B^2=2\ A D^2

In an isosceles triangle A B C with A B=A C , B D is perpendicular from B to the side A C . Prove that B D^2-C D^2=2\ C D A D