Solve for a, b, c and d when `((b+c,c+a),(7-d,6-c))=((9-d,8-d),(a+b,a+b))`

Solve for a,b,c,d when [[b+c,c+a],[7-d,6-c]]=[[9-d,8-d],[ a+b, a+b]]

If A={a,b},B={c,d},C={d,e} then {(a,c),(a,d)(a,e),(b,c),(b,d),(b,e)}=

If A={a,b},B={c,d},C={d,e} then {(a,c),(a,d),(a,e),(b,c),(b,d),(b,e)}=

Let the positive numbers a , b , c , d be in AP. Then a b c ,a b d ,a c d ,b c d are

If A=[[a, b],[ c ,d]] , then a d j\ A is (a) [[-d,-b],[-c, a]] (b) [[d,-b],[-c ,a]] (c) [[d, b],[ c, a]] (d) [[d, c],[ b ,a]]

If A={a,b},B={c,d},C={d,e}, then : {(a,c),(a,d),(a,e),(b,c),(b,d),(b,e)} is :

(a)If A=[a,b],B=[c,d],C=[d,e] then {(a,c),(a,d),(a,e),(b,c),(b,d),(b,e)}=………

If a,b,c and d are in H.P.,then prove that (b+c+d)/a,(c+d+a)/b,(d+a+b)/c and (a+b+c)/d, are in A.P.

If D=abs((a,b,c),(c,a,b),(b,c,a)) and D'=abs((b+c,c+a,a+b),(a+b,b+c,c+a),(c+a,a+b,b+c)) prove that D'=2D