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200 mL of a very dilute aqueous solution...

200 mL of a very dilute aqueous solution of a protein contains `1.9` gm of the protein . If osmotic rise of such a solution at 300K is found to be 38 mm of solution then calculate molar mass of the protein .
(Take R = `0.008` L atm `mol^(-1) K^(-1)`)

A

24630 g/ mole

B

123150 milli g / mole

C

517230 g / mole

D

62016 g / mole

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The correct Answer is:
D
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