Home
Class 12
CHEMISTRY
Availabe are 1L of 0.1 M NaCl and 2L 0.2...

Availabe are `1L` of `0.1` M NaCl and 2L `0.25` M `CaCl_(2)` solution . Using only these two solutions what maximum volume of a solution can be prepared having `[Cl^(-)] = 0.34` M exactly ? Both electrolytes are strong .

A

`2.5 `L

B

`2.4`L

C

`2.3`L

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • LIQUID SOLUTIONS

    GRB PUBLICATION|Exercise 5|15 Videos
  • LIQUID SOLUTIONS

    GRB PUBLICATION|Exercise 8|12 Videos
  • LIQUID SOLUTIONS

    GRB PUBLICATION|Exercise 18|9 Videos
  • IONIC EQUILIBRIUM

    GRB PUBLICATION|Exercise All Questions|526 Videos
  • METALLUGY

    GRB PUBLICATION|Exercise Subjective type|1 Videos

Similar Questions

Explore conceptually related problems

Available solutions are 1L of 0.1 M NaCl and 2L of 0.2 M CaCl_2 .Using only these two solutions what maximum volume of a solution can be prepared having [Cl^(-)]=0.34 M exactly.Both electrolytes are strong

When 100 mL of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :

If 20.0 mL of 0.1 M calcium chloride and 60mL of 0.2 M CaCl_(2) are mixed, what will be the molarity of the final solution ?

You are supplied with supplied with 500mL each of 2NHCL and HCL solutions.What is the maximum volume of 2M HCL solution that you can prepare using only these two solution ?

The Van't Hoff factor for 0.1 M CaCl_(2) solution is 2.74. The degree of dissociation is

Elevation in boiling point of 0.1 m CaCl_(2) , solution less / more than 0.1 m NaCl solution.

The time taken to convert 1 L of 1 M NaCl solution to 1 L of 1 M NaCl solution by passing 1 amperer current is

Equal volumes of 0.1 M NaCl and 0.06 M CaCl_(2) solutions are separated by a semi - permeable membrane in container. For this system, choose the correct answer

The volumes of two HCl solution A (0.5 M) and B (0.1M) to be mixed for preparing 2 L of 0.2 M HCl are