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The Henry's law constant for the solubil...

The Henry's law constant for the solubility of `N_(2)` gas in water at `298 K` is `1.0 xx 10^(5) atm`. The mole fraction of `N_(2)` in air is `0.8`. The number of moles of `N_(2)` from air dissolved in `10` moles of water at `298 K` and `5 atm`. Pressure is:

A

`4xx10^(-4)`

B

`4.0xx10^(-5)`

C

`5.0xx10^(-4)`

D

`4.0xx10^(-6)`

Text Solution

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The correct Answer is:
A
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