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For the given electrolyte A(x)B(y). The ...

For the given electrolyte `A_(x)B_(y)`. The degree of dissociation `'alpha'` can be given as:

A

`alpha = (i-1)/(x + y - 1)`

B

`I = (1-alpha) + xalpha + yalpha`

C

`alpha = (1-i)/(1-x-y)`

D

`i = (x+y - 1) alpha`

Text Solution

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The correct Answer is:
A, B, C
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