Home
Class 12
CHEMISTRY
60 g of a non-volatile solid AB(having c...

60 g of a non-volatile solid AB(having crystals like NaCl or CaCl) is dissolved in 0.50 kg water. The normal boiling point of solution is found to be `102.08^(@)` C. The molal elevation of water is 0.52 K-kg `mol^(-1)`. The density of solid AB is 6.25 g`//cm^(3)` and the edge-lengthh of unit cell is 400 pm.The coordination number for `A^(+)` ion in the solid is :
(`N_(A)=6xx10^(23))`

Text Solution

Verified by Experts

The correct Answer is:
6
Promotional Banner

Topper's Solved these Questions

  • LIQUID SOLUTIONS

    GRB PUBLICATION|Exercise 19|9 Videos

  • LIQUID SOLUTIONS

    GRB PUBLICATION|Exercise 23|8 Videos

  • LIQUID SOLUTIONS

    GRB PUBLICATION|Exercise 15|10 Videos

  • IONIC EQUILIBRIUM

    GRB PUBLICATION|Exercise All Questions|526 Videos

  • METALLUGY

    GRB PUBLICATION|Exercise Subjective type|1 Videos

Similar Questions

Explore conceptually related problems

A solution contains 0.524 g of camphor ( molar mass = 152 g/ mol dissolved in 36.8 g of ether (boiling point =34.6^(@) C) . The molal elevation constant per 100 g of ether is 19.4 K kg mol ^(-1) . The boiling point of the solution is _______.

The elevation in boiling point of a solution of 9.43 g of MgCl_2 in 1 kg of water is ( K_b = 0.52 K kg mol^(-1) , Molar mass of MgCl_2 = 94.3 g mol^(-1) )

A solution containg 12 g of a non-electrolyte substance in 52 g of water gave boiling point elevation of 0.40 K . Calculate the molar mass of the substance. (K_(b) for water = 0.52 K kg mol^(-1))

A solution containing 6 g of a solute dissolved in 250 cm^(3) of water gave an osmotic pressure of 4.5 atm at 27^(@)C . Calculate the boiling point of the solution.The molal elevation constant for water is 0.52^@ C per 1000 g.