If x,y,z are non-negative integers such that `x+y+z+xy+yz+zx+xyz=2018`, then `x+y+z` equals `(i) 674 (ii) 1010 (iii) (iv) 908 `

Let xy,z be three non-negative integers such that x+y+z=10. The maximum possible value of xy+yz+zx is

If f(x,y,z) =xy + yz + zx, then f_(x) - f_(z) is equal to

if x+y+z=1 and xy+yz+zx=1/3 then find x:y:z

Factorize 1+x+y-z+xy-yz-zx-xyz

The system of equations 3x+y+2z=6,xyz=-5,3xy+2yz+6xz=-1 has a solution (x,y,z), where x,y,z are integers.Then the value of (x+z)/(y) is equal to (i)0(ii)1(iii)2(iv)3

If (x + y + z) = 16 and xy + yz + zx = 75, then x ^(3) + y ^(3) + z ^(3) - 3xyz is