(81)^(0.16)times(81)

Simplify (81)^(0.16) xx (81)^(0.09)

sqrt(4sqrt(81))times(81)^(-1/4)=

Find value of (81)^(0.16)xx81^(0.09)

((64)/(27))^((2)/(3))times((9)/(16))^((3)/(2))times((81)/(256))^((3)/(4))=((3)/(4))^(x) then x=

sqrt((81)/(64)sqrt((81)/(64)sqrt((81)/(64)sqrt((81)/(64)))).........oo=)

sqrt((81)/(64)sqrt((81)/(64))sqrt((81)/(61))sqrt((81)/(64))...oo)=

If 3^(4x)=(81)^(-1)and(10)^((1)/(y))=0.0001, value of 2^(-x) xx 16^(y) .

If 3^(4x)=(81)^(-1) and (10)^(1//y)=0.0001 , find the value of 2^(-x)xx(16)^(y) .

If in a binomial distribution n=4,P(X=0)=(16)/(81), then P(X=4) equals (1)/(16) b.(1)/(81) c.(1)/(27) d.(1)/(8)

Find the value of 1/(81^n)-(10)/(81^n)C_1+(10^2)/(81^n)C_2-(10^3)/(81^n)C_3++(10^(2n))/(81^n) .