Starting from the origin a body oscillates simple harmonically with a period of 2s . After time `(1)/(x)` second willthe kinetic energy be `75%` of its total energy , then value of x is

Starting from the mean position a body oscillates simple harmonically with a period of 2 s.

Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 25% of the total energy?

Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?

Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?

Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?

Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?

Starting from the origin, a body oscillates simple harmonically with a period of 2s. After a certain time (t) its kinetic energy will be 75% of the total energy. What should be the value of 1/t("in "s^(-1)) ?

starting from the mean position a body oscillates simple harmonically with an amplitude of 2m and a period of 2s . after what time will its kinetic energy be 75% of the total energy?