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In the adjoining figure AB= AC and D is ...

In the adjoining figure AB= AC and D is the mid-point of BC. Use SSS rule of congruency to show that `triangle ABD ~=triangle ACD` AD is bisector of `angle A` AD is perpendicular to BC

Text Solution

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In`/_ABD and /_ACD`
AB=AC(GIVEN)
BD=DC(D is mid point of BC)
AD=AD
so,`/_ABDcong/_ACD`
so, `angleBAD=angleCAD`
and`angleADB=angleADC=180^o/2=90^o`
this means AD is perpendicular BC
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