One Mev positron encounters one MeV elec...

One Mev positron encounters one MeV electron travelling in opposite direction. What is the wavelength travelling in opposite direction. What is the wavelength of photons produced, given rest mass energy of electron or positron `=0.512MeV` ? Take `h=6.62xx10^(-34)J-s`.

Similar Questions

Explore conceptually related problems

A 1 MeV positron encounters a 1 MeV electron travelling in opposite direction. The total energy released is (In MeV )

The energy of a photon of wavelength 4000 Å is (use h=6.66xx10^(-34) J-s)

What is the momentum of electron beam of wavelength 4Å? (h=6.62xx10^(-34)Js)

Give the value of speed and rest mass of photon . Determine the wavelength of photon energy 10^(10) eV (Given h=6.625xx10^(-34) J s)

Find the momentum of an electron having wavelength 2A^(0)(h=6.62xx10^(-34)Js)

Calculate the energy in eV for each photon for light of wavelength 4950Å . Take h=6.6xx10^(-34)J-s

Calculate the wavelength, wave number and frequency of photon having an energy to three electron volt. (h=6.62xx10^(-27) erg-sec) .

Calculate the wavelength of a photon of energy 10^(10) eV (electron volt(. Given Planck.s constant h=6.625 xx 10^(-34) Js (Joule Second).