[" 18."3x-2y=12],[" 4"x-5y=16]

Solve: 3x+2y=29,5x-y=18

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

The maximum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombous is

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

Solve: 3x+2y=29,5x-y=18.

3 x + 2y = 12 , 5x - 2y = 4 .

Solve : 3x+2y = 29, 5x - y = 18

Solve the following simultaneous linear equations by drawing graphs for them : (xiv) 3x+5y=12, 3x-5y + 18 =0

Solve : 2x-y+z=4 , x+3y+2z=12 , 3x+2y+3z=16

{:(3x + 5y = 12),(3x - 5y = - 18):}