A parallel plate capacitor has a plate separation of `2mm` and use a dielectric (whose dielecric strength is `200 kV//cm)` as an insulator. The maximum potential difference that can be applied to the terminals of the capacitor is

A parallel plate capacitor has an area of 4cm^2 and a plate separation of 2mm:- Calculate its capacitance.

A parallel plate capacitor has capacitor has a capacity of 6 muF when dielectric medium separting the plates.

The is one parallel plate air capacitor having plate area 40 cm^(2) and separation between the plates equal to 0.1 mm. Dielectric strength of air is 3xx 10^(6) V/m. find maximum rms voltage that can be applied across capacitor without electric breackdown.

A parallel plate capacitor, with plate area A and plate separation d, is filled with a dielectric slabe as shown. What is the capacitance of the arrangement ?

The plates of a parallel plate capacitor are charged up to 200 V. A dielectric slab of thickness 4 mm is inserted between its plates. Then, to maintain the same potential difference between the plates of the capacitor, the distance between the plates increased by 3.2 mm. The dielectric constant of the dielectric slab is

The plates of a parallel plate capacitor are charged up to 200 V. A dielectric slab of thickness 4 mm is inserted between its plates. Then, to maintain the same potential difference between the plates of the capacitor, the distance between the plates increased by 3.2 mm. The dielectric constant of the dielectric slab is

A parallel plate capacitor has two layers of dielectrics as shown in figure. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is