Find for what values of `x` the following functions would be identical.
`f(x)=log(x-1)-log(x-2)` and `g(x)=log((x-1)/(x-2))`

Are the following functions identical ? f(x) = log ( x-2) + log (x-3) and phi (x) log (x-2) (x-3)

The function f(x) =log(x-1)-log(x-2) and g(x) =log((x-1)/(x-2)) are identical on

If the function f(x)=log(x-2)-log(x-3) and g(x)=log((x-2)/(x-3)) are identical, then

If the function f(x)=log(x-2)-log(x-3) and g(x)=log((x-2)/(x-3)) are identical, then

Are the following functions identical ? f(x) = log x^2 and phi (x) = 2 log x

If function f and g given by f (x)=log(x-1)-log(x-2)and g(x)=log((x-1)/(x-2))"are equal" then x lies in the interval.

Let f(x) = ln(x-1)(x-3) and g(x) = ln(x-1) + ln(x-3) then,

Which of the following functions are identical? f(x)=1nx^(2) and g(x)=2ln xf(x)=log_(x)e and g(x)=(1)/(log x)f(x)=sin(cos^(-1)x) and g(x)=cos(sin^(-1)x) none of these

Prove that the following functions are strictly increasing: f(x)=log(1+x)-(2x)/(2+x) for x > -1

Prove that the following functions are strictly increasing: f(x)=log(1+x)-(2x)/(2+x) for x > -1