If `13.1g` of `Na_(2) SO_(4) XH_(2)O` contains `6g` of `H_(2)O`, the value of `X` is

Na_(2)O_(2) + H_(2)SO_(4) to

Na_(2)SO_(4).xH_(2)O has 50% H_(2)O . Henxe, x is :

Na_(2)SO_(4).xH_(2)O has 50% H_(2)O . Henxe, x is :

Na_(2)SO_(4).xH_(2)O has 50% H_(2)O . Henxe, x is :

13.4 g of a sample of unstable hydrated salt Na_(2)SO_(4).XH_(2)O was found to contains 6.3 g of H_(2) O . The number of molecular of water of crystalistion is

13.4 g of a sample of unstable hydrated salt Na_(2)SO_(4).XH_(2)O was found to contains 6.3 g of H_(2) O . The number of molecular of water of crystalistion is

The compound Na_(2)CO_(3).xH_(2)O has 50% H_(2)O by mass. The value of 'x' is

Na_(2)CO_(3) have water of crystallisation and its formula is Na_(2)CO_(3)*xH_(2)O .If 2.32g" of Na_(2)CO_(3)*xH_(2)O is heated then it loose "1.26g" of water,the value of "x" is assume all water of crystalline are removed when Na_(2)CO_(3)*xH_(2)O is heated