Radius of an electron moving in a circle in constant magnetic field is two times that of an `alpha` particle in the same field. Then de-Broglie wavelength of electrons is x-times of the `alpha`-particle Here x is

The radius of and alpha -particle moving in a circle in a constant magnetic field is half of the radius of and electron moving in circular path in the same field. The de Broglie wavelength of alpha -particle is n times that of the electron. Find n (an integer).

The radius of and alpha -particle moving in a circle in a constant magnetic field is half of the radius of and electron moving in circular path in the same field. The de Broglie wavelength of alpha -particle is n times that of the electron. Find n (an integer).

A proton, a neutron, an electron and alpha -particle have the same energy. Then their de-Broglie wavelengths compare is

A proton, a neutron, an electron and an alpha -particle have same energy. Then their de-Broglie wavelengths compare as

A proton ,a neutron ,an electron and an alpha -particle have same energy.Then their de-Broglie wavelength compare as

A proton, a neutron, an electron and an alpha -particle have same energy. Then their de-Broglie wavelengths compare as

A proton, a neutron, an electron and an alpha -particle have same energy. Then their de-Broglie wavelengths compare as

A proton , a neutron , an electron and an alpha -particle have same energy. Then their de Broglie wavelengths compare as

An electron and an alpha particle have the same kinetic energy. How are the de-Broglie wavelengths associated with them related?