Calculate the area of paper required to construct a parallel plate capacitant of `0.004 muF`, if the dielectric constant of paper be `2.5` and its thickness `0.025 mm`.

Find the length of the paper used in a capacitor of capacitance 2muF , if the dielectric constant of the paper is 2.5 and its width and thickness are 50 mm and 0.05mm, respectively.

Briefly explain the principle of a capacitor. Find the expression for the capacitance of a parallel plate capacitor when a dielectric slab of dielectric constant k and thickness t=d/2 but of same area on the plates is inserted between the capacitor plate.

A parallel plate capacitor has a capacitance of 50muF in air and 110muF when immersed in oil, the dielectric constant of the oil is

The capacitance of a capacitor made by a thin metal foil is 2muF . If the foil is filled with paperr of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of the paper is 400 mm. what is the length of foil?

The capacitance of a capacitor made by a thin metal foil is 2muF . If the foil is filled with paperr of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of the paper is 400 mm. what is the length of foil?

A parallel plate capacitor has an area of 4cm^2 and a plate separation of 2mm:- Calculate its capacitance.

Separation between the plates of a parallel plate capacitor is d and the area of each plates is A . When a slab of material of dielectric constant k and thickness t(t lt d) is introduced between the plates. Its capacitance becomes

Separation between the plates of a parallel plate capacitor is d and the area of each plates is A . When a slab of material of dielectric constant k and thickness t(t lt d) is introduced between the plates. Its capacitance becomes