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" ii "|(1)/(x-3)-(1)/(x+5)=(1)/(6)|x!=3,...

" ii "|(1)/(x-3)-(1)/(x+5)=(1)/(6)|x!=3,-5

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(1)/((x-3))-(1)/((x+5))=(1)/(6),(x!=3,-5)

solve for x,(1)/(x-3)-(1)/(x+5)=(1)/(6)

Solve: (1)/(x-3)+(1)/(x+5)=(1)/(6) .

Solve each of the following quadratic equations: (i) (1)/(x-1)-(1)/(x+5)=(6)/(7),xne1,-5 (ii) (1)/(2x-3)+(1)/(x-5)=1(1)/(9),xne(3)/(2),5

((1)/(x-3)-(3)/(x(x^(2)-5x+6)))

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

(ii) [(1)/(2)x^(1/3)+x^(-1/5)]^(8)

5x-1/3(x+1)=6(x+1/30)

5x-1/3(x+1)=6(x+1/30)