[" 부 "4" .Show that "x=-(bc)/(ad)" is a solution of the quadratic eque "],[ad^(2)((ax)/(b)+(2c)/(d))x+bc^(2)=0" ."]

Show that x=-(bc)/(ad) is a solution of the quadratic equation ad^(2)((ax)/(b)+(2c)/(d))x+bc^(2)=0

(a^(2)-b^(2)-c^(2)+d^(2))^(2)-4(ad-bc)^(2)

The roots of the equation (a^(2)+b^(2))x^(2)-2(bc+ad)x+(c^(2)+d^(2))=0 are equal if

If f(x)=(ax+b)/(cx+d'),ad-bc!=0 is inverse of itself then

If (ad-bc)/(a-b-c+d) = (ac-bd)/(a-b+c-d) then show that each ratio = (a+b+c+d)/4

Prove that, if the roots of the equation (a^2+b^2)x^2+2(bc+ad)x+(c^2+d^2)=0 be real, then they are equal.

If Rs.x are divided between A and B in the ratio (a)/(b);(c)/(d) then A gets rupees (adx)/(ab+cd)b(adx)/(ad+bc) c.(abx)/(ad+bc)d.(abx)/(ac+bd)

Prove that the quadratic equation (a^2+b^2)x^2+2(ac+bd)x+(c^2+d^2)=0 has no real roots when ad!=bc .