`cosec theta=sqrt(n+1),` then `cos theta=` `(i) sqrt ((n+1)/(n-2)) (ii) sqrt ((n+1)/(n-1)) (iii) sqrt((n)/(n-1)) (iv)sqrt((n)/(n+1)) `

lim_(n to oo)(1)/(n)(1+sqrt((n)/(n+1))+sqrt((n)/(n+2))+....+sqrt((n)/(4n-3))) is equal to:

lim_(n to oo)(1)/(n)(1+sqrt((n)/(n+1))+sqrt((n)/(n+2))+....+sqrt((n)/(4n-3))) is equal to:

lim_(ntooo)(3)/(n){1+sqrt((n)/(n+3))+sqrt((n)/(n+6))+sqrt((n)/(n+9))+.........+sqrt((n)/(n+3(n-1)))}

lim_ (n rarr oo) (3) / (n) [1 + sqrt ((n) / (n + 3)) + sqrt ((n) / (n + 6)) + sqrt ((n) / (n +9)) + ...... + sqrt ((n) / (n + 3 (n-1)))

If f (theta)=4/3 (1- cos ^(6) theta - sin ^(6)theta), then lim _(xtoo) 1/n [sqrt(f ((1)/(n)))+sqrt(f ((2)/(n)))+sqrt(f((n)/(n)))]=

If f (theta)=4/3 (1- cos ^(6) theta - sin ^(6)theta), then lim _(ntooo) 1/n [sqrt(f ((1)/(n)))+sqrt(f ((2)/(n)))+sqrt(f((n)/(n)))]=

lim_(n->oo) ((sqrt(n^2+n)-1)/n)^(2sqrt(n^2+n)-1)

Which of following is correct (where n in N ) ? (i) sin theta = (n+1)/n (ii) sin theta = (n^2 + 1)/(n+1) (iii) sec theta = (n+2)/(n-1) (iv) sec theta = n/(sqrt(n^2 +1))

If the major axis is n times the minor axis of the ellipse,then eccentricity is 1) (sqrt(n-1))/(n) 2) (sqrt(n-1))/(n^(2)) 3) (sqrt(n^(2)-1))/(n^(2)) 4) (sqrt(n^(2)-1))/(n)

lim_(n rarr oo)(sin(1)/(sqrt((n))))((1)/(sqrt(n+1)))^(+(1)/(sqrt(n+2))+(1)/(sqrt(n+2)))