The pole strength of a bar magnet is 48 ampere-metre and the distance between its poles is `25cm`. The moment of the couple by which it can be placed at an angle of `30^(@)` with the uniform magnetic intensity of flux density `0.15 "newton"//"ampere-metre"` will be
A
12 Newton × metre
B
18 Newton × metre
C
0.9 Newton × metre
D
None of the above
Text Solution
Verified by Experts
The correct Answer is:
C
Topper's Solved these Questions
MAGNETISM
ERRORLESS |Exercise Magnet and it s Properties|15 Videos
MAGNETISM
ERRORLESS |Exercise Earth Magnetism|8 Videos
MAGNETIC EFFECT OF CURRENT
ERRORLESS |Exercise Exercise|394 Videos
RAY OPTICS
ERRORLESS |Exercise SET|25 Videos
Similar Questions
Explore conceptually related problems
The pole strength of a bar magnet is 48 ampere-metre and the distance between its poles is 25 cm. The amount of the coupled force by which it can be placed at an angle 30^@ with the uniform magnetic intensity of flux density 0.15 newton/ampere-metre will be
The pole strength of a bar magnet is 48A-m and the distance between its poles is 25 cm . The torque by which it can be held at an angle of 30^(@) with the uniform magnetic field of strength 0.15 Wb//m^(2) , will be
The dipole moment of a short bar magnet is 1.25 A-m^(2) . The magnetic field on its axis at a distance of 0.5 metre from the centre of the magnet is
A short bar magnet has a magnetic moment of 10 Am^(2) .If its length is 10 cm,then the pole strength of the dipole is
A bar magnet of length 10cm and pole strength 2 Am makes an angle 60^(0) with a uniform magnetic field of induction 50T . The couple acting on it is
If a magnet of length 10cm and pole strength 40 A-m is placed at an angle of 45^(@) in an uniform induction field of intensity 2xx10^(-4)T , the couple acting on it is
The force acting on each pole of a magnet when placed in a uniform magnetic field of 7A//m is 4.2xx10^(-4)N . If the distance between the poles is 10 cm , the moment of the magnet is
The length of a bar magnet is 10 cm and its pole strength is 10^(-3) Weber. It is placed in a magnetic field of induction 4 pi × 10^(-3) Tesla in a direction making an angle 30^(@) with the field direction. The value of torque acting on the magnet will be –
The distance between the poles of a horse shoe magnet is 0.1 m and its pole strength is 0.01 amp-m. The induction of magnetic field at a point midway between the poles will be
