Home
Class 12
PHYSICS
A magnetic needle lying parallel to a ma...

A magnetic needle lying parallel to a magnetic field requires `W units` of work to turn it through `60^(@)`. The torque needed to maintain the needle in this position will be

A

`sqrt(3)W`

B

W

C

`(sqrt(3))/(2)W`

D

2W

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM

    ERRORLESS |Exercise Magnet and it s Properties|15 Videos

  • MAGNETISM

    ERRORLESS |Exercise Earth Magnetism|8 Videos

  • MAGNETIC EFFECT OF CURRENT

    ERRORLESS |Exercise Exercise|394 Videos

  • RAY OPTICS

    ERRORLESS |Exercise SET|25 Videos

Similar Questions

Explore conceptually related problems

A magnetic needle lying parallel to a magnetic field requires X units of work to turn it through 60^(@) . The torque necessary to maintain the needle in this position is

A magnetic needle suspended parallel to a magnetic field requires sqrt3J of work to turn it through 60^@ . The torque needed to maintain the needle in this postion will be:

A magnetic needle lying parallel to the magnetic field required W units of work to turn it through an angle 45^@ The torque required to maintain the needle in this position will be

A magnetic needle lying parallel to a magnetic field requires W units of work to turn through 60^(@) . The external torque required to maintain the magnetic needle in this position is

A magnetic needle lying parallel to a magnetic field needs 2J work to turn it through 60^@ . Calculate the torque required to maintain the needle in this position.