The work done in turning a magnet of magnetic moment 'M' by an angle of `90^(@)` from the meridian is 'n' times the corresponding work done to turn it through an angle of `60^(@)`, where 'n' is given by
A
1/2
B
2
C
1/4
D
1
Text Solution
Verified by Experts
The correct Answer is:
B
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