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At a place the earth's horizontal compon...

At a place the earth's horizontal component of magnetic field is `0.36xx10^(-4) "Weber"//m^(2)`. If the angle of dip at that place is `60^(@)`, then the vertical component of earth's field at that place in `"Weber"//m^(2)` will be approxmately

A

`0.12xx10^(-4)`

B

`0.24xx10^(-4)`

C

`0.40xx10^(-4)`

D

`0.62xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
D
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