A short magnet of moment `6.75 Am^(2)` produces a neutal point on its axis. If horizontal component of earth's magnetic field is `5xx10^(-5) "Wb"//m^(2)`, then the distance of the neutal point should be
A
10 cm
B
20 cm
C
30 cm
D
40 cm
Text Solution
Verified by Experts
The correct Answer is:
C
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