A current carryingcoil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be `H_(0)` and magnetic field inside the loop is H. If a magnet is suspended inside the loop, it makes angle `theta` with H. Then `theta`=
A
`tan^(-1)((H_(0))/(H))`
B
`tan^(-1)((H)/(H_(0)))`
C
`cosec^(-1)((H)/(H_(0)))`
D
`cot^(-1)((H_(0))/(H))`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
MAGNETISM
ERRORLESS |Exercise Magnet and it s Properties|15 Videos
MAGNETISM
ERRORLESS |Exercise Earth Magnetism|8 Videos
MAGNETIC EFFECT OF CURRENT
ERRORLESS |Exercise Exercise|394 Videos
RAY OPTICS
ERRORLESS |Exercise SET|25 Videos
Similar Questions
Explore conceptually related problems
The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is
At a certain place the angle of dip is 30^(@) and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is
At certain place, the horizontal component of earth's magnetic field is 3.0G and the angle dip at the place is 30^(@) . The magnetic field of earth at that location
The angle of dip at a certain place is 30^(@) . If the horizontal component of the earth's magnetic field is H, the intensity of the total magnetic field is
At a place the angle of dip is 30 degrees. If the horizontal component of the earth's magnetic field is H, then the total field intensity will be given by
What is the horizontal component of Earth's magnetic field? If the horizontal and vertical components of Earth's magnetic field are equal then what is the angle of dip?
Let V and H be the vertical and horizontal components of earth's magnetic field at any point on earth. Near the north pole
Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G