A small bar magnet `A` oscillates in a horizontal plane with a period `T` at a place where the angle of dip is `60^(@)`. When the same needle is made to oscillate in a vertical plane coinciding with the magnetic merdian, its period will be
A
`(T)/(sqrt(2))`
B
T
C
`sqrt(2)T`
D
`2T`
Text Solution
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The correct Answer is:
A
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