The time period of oscillation of a bar magnet suspended horizontaliy along the magnetic meridian is `T_(0)`. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be
A
`(T_(0))/(2)`
B
`(T_(0))/(sqrt(2))`
C
`sqrt(2)T_(0)`
D
`2T_(0)`
Text Solution
Verified by Experts
The correct Answer is:
C
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