A magnet makes `40` oscillations per minute at a place having magnetic field intensity of `0.1xx10^(-5)T`. At another place, it takes 2.5 sec to complete one vibrating. The value of earth's horizontal field at that place is
A
`0.25xx10^(dot)T`
B
`0.36xx10^(dot)T`
C
`0.66xx10^(dot)T`
D
`1.2xx10^(dot)T`
Text Solution
Verified by Experts
The correct Answer is:
B
Topper's Solved these Questions
MAGNETISM
ERRORLESS |Exercise Magnet and it s Properties|15 Videos
MAGNETISM
ERRORLESS |Exercise Earth Magnetism|8 Videos
MAGNETIC EFFECT OF CURRENT
ERRORLESS |Exercise Exercise|394 Videos
RAY OPTICS
ERRORLESS |Exercise SET|25 Videos
Similar Questions
Explore conceptually related problems
A magnet makes 40 oscillations per minute at a place having magnetic field of 0.1 xx 10^(-5) T . At another place, " it take 2.5 s to complete one vibration. If the value of the earth's horizontal field at that place is y xx 10^(-6) T . then find y .
At a certain place, a magnet makes 30 oscillations per minute. At another place, the magnetic field is double. What is the its time period ?
At a certain place a magnet makes 30 oscillations per minute. At another place where the magnetic field is double, its time period will be
At a place where angle of dip is 45^(@) , a magnet oscillates with 30 oscillations per minute. At another place where angle of dip is 60^(@) , the same magnet makes 20 oscillations per minute The ratio of total magnetic fields at the two places is
A magnet is suspended in such a way that it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place where dip angle is 30^(@) and 15 oscillations minute at a place where dip angle is 60^(@) . The ratio of total earth's magnetic field at the two places is
A magnet freely suspended in a vibration magnetometer makes 10 oscillations per minute at a place A and 20 oscillations per minute at a place B. If the horizontal component of earth's magnetic field at A is 36xx10^(-6)T , then its value at B is