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If the wavelength of light in vacuum be ...

If the wavelength of light in vacuum be `lambda`, the wavelength in a medium of refractive index n will be

A

`n lambda`

B

`lambda/n`

C

`lambda/n^(2)`

D

`n lambda`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The wavelength of light in vacuum is lambda . The wavelength of light in a medium of refractive index n will be

    A
    `n lambda `
    B
    `(lambda)/(n)`
    C
    `(lambda)/(n^(2))`
    D
    `(n^(2))/(lambda )`

  • If c is velocity of light in vacuum and v is the velocity of light in a medium of refractive index mu , then

    A
    `mu = c//v`
    B
    `mu = v//c`
    C
    `mu = (c + v)/(c - v)`
    D
    `mu = (c - v)/(c + v)`

  • If the speed of light in vacuum is C m//sec, then the velocity of light in a medium of refractive index 1.5 is.

    A
    `1.5xxC`
    B
    `C`
    C
    `(C )/(15)`
    D
    Can have any velocity

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