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Angle of deviation (delta) by a prism (r...

Angle of deviation `(delta)` by a prism (refractive index = `mu` and supposing the angle of prism A to be small) can be given by

A

`delta = (mu - 1) A`

B

`delta = (mu + 1) A`

C

`delta = (sin (A + delta)/(2))/(sin (A)/(2))`

D

`delta = (mu - 1)/(mu + 1) A`

Text Solution

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The correct Answer is:
a
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