The far point of a myopia eye is at 40 c...

The far point of a myopia eye is at `40 cm`. For removing this defect, the power of lens required will be

`40 D`

`- 4 D`

`- 2.5 D`

`0.25 D`

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The far point of a myopic person is 120 cm in front of the eye. Calculate the power of the lens required to enable the person see distant object clearly.

The far point of a myopic eye is at 50 cm . Calculate the power of the lens to correct his vision.

The near point of a hypermetropic person is 50 cm from the eye. What is the power of the lens required to enable him to read clearly a book held at 25 cm from the eye ?

The near point of a hypermetropic eye is 1 m. What is the nature and power of the lens required to correct this defect ? (Assume that the near point of the normal eye is 25 cm).

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