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The length of an astronomical telescope ...

The length of an astronomical telescope for normal vision (relaxed eye) ( `f_(o)` = focal length of objective lens and `f_(e)` = focal length of eye lens) is

A

`f_(o) xx f_(e)`

B

`(f_(o))/(f_(e))`

C

`f_(o)+f_(e)`

D

`(f_(o)-f_(e))`

Text Solution

Verified by Experts

The correct Answer is:
c
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Knowledge Check

  • To increase the magnifying power of telescope ( f_(o) = focal length of the objective and f_(e) = focal length of the eye lens)

    A
    `f_(o)` should be large and `f_(e)` should be small
    B
    `f_(o)` should be small and `f_(e)` should be large
    C
    `f_(o)` and `f_(e)` both should be large
    D
    `f_(o)` and `f_(e)` both should be small

  • Focal length of eye lens is changed by

    A
    Pupil
    B
    Iris
    C
    Cornea
    D
    Ciliary body

  • Focal length of eye lens is changed by

    A
    Pupil
    B
    Iris
    C
    Cornea
    D
    Ciliary body

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    The optical length of an astronomical telescope with magnifying power of ten for normal vision is 44 cm . What is the focal length of the objective ?

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