A 196 dyne force acts between two point charges separated by a distance 6 cm. If the magnitude of one charge is 4 times that of the other, calculate the charges on each.

Explanation

From coulomb's law `F=(q_(1)q_(2))/(r^(2))`
Suppose `q_(1)=q`, so `q_(2)=4q`
Givne `F=196dyn, r=6cm`
`:.196=(qxx4q)/(6^(2))` or `q^(2)=49xx6^(2)`
or `q=24` stat C
`:.` The other charge `=4xx42=169` statC.