A thin straight wire of length 40 cm placed in vacuum has ` 20 mu C ` charge. Calculate the electric field intensity at a distance 15 cm from the wire.

Explanation

Electric field intensity at a distance of 15 cm from the straight wire,
` E = (1 ) /( 4pi in _ 0) * ( 2pi ) /(x ) " " [ lamda ` = charge per unit length of the wire ` = ( 20 xx 10 ^( - 6))/( 40 xx 10 ^( - 2)) C * m^( - 1 )] `
` = ( 9 xx 10 ^( 9) xx 2 xx 20 xx 10 ^( - 6 ))/( 15 xx 10 ^( -2 ) xx 40 xx 10 ^( -2 ) ) = 6 xx 10 ^(6 ) N * C ^( - 1 ) `