Show that the ratio of electric fields at equal distances on the axis and on the perpendicular bisector for a small dipole is 2 : 1.

What is the ratio of the intensity of the electric field at a particlular distance on the axis to that on the perpendicular bisector of a very small dipole ?

The ratio of the magnetic fields at the same distance (r) along the magnetic axis and along the perpendicular bisector of the magnet (rgtgtl , the length of the magnet ) is n :1 . What is the value of n ?

If E_1 be the electric field strength of a short dipole at a point on the axis and E_2 that on the perpendicular bisector at the same distance , then

What is electric dipole? Find electric field intensity at a point on the? perpendicular bisector of an electric dipole.

The electric field due to a small dipole of length 2l at distance r ( rgtgtl) from the centre of the dipole on the axial line is E. What is the distance of the point on the perpendicular bisector of the dipole from its centre in which the electric field intensity is E ?

Two charges +q and -q separated by a distance of 3xx10^(-12)m in air form an electric dipole. If the intensity of the electric field is 3.3xx10^(-32)N.C^(-1) at a distance 3 cm from the dipole on the perpendicular bisector, what is value of q?

Why electric fields just outside the surface of a conductor is perpendicular to the surface?

The direction of the intensity of the electric field at a point on the perpendicular bisector of an electric dipole ( vec(p) = electric dipole moment ) is

An electric dipole is formed by placing charges pm 20 xx 10 ^( -6 ) C at a distance 2 mm. Calculate the electric field at a point on the perpendicular bisector of the axis of the dipole situated at a distance 10 cm from the midpoint of the dipole.