A small electric dipole is placed at origin with its dipole moment directed along positive X-axis. The direction of electric field at point `( 2,2sqrt(2),0)` is along

Options

A. `-`Z-axis
B. `+`Z-axis
C. `-Y`-axis
D. `+Y`-axis

Explanation

x=2 , `y=2sqrt(2), z=0`
`:. tan theta =(2 sqrt(2))/(2)=sqrt(2) :. cot theta =(1)/(tan theta)=(1)/(sqrt(2))`
Let intensity make an angle `phi` with OP.
`:. tan phi =(1)/(2) tan theta `
`=(1)/(2) xx sqrt(2) `
`=(1)/(sqrt(2))=cot theta `
`:. phi + theta=90^(@) or , phi=90^(@)-theta `
So , `vec(E)` is along `+Y-axis `