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A circular copper ring of radius r, plac...

A circular copper ring of radius r, placed in vacuum, has charge q on it. The electric field intensity at the centre of the ring is `E_(1)`. The electric field intensity on the axis of the ring at a distance x from its centre is `E_(2)`. The value of `E_(2)` will be maximum when `x=x'`
What is the value of `E_(1)`?

A

0

B

`qxxpi r^(2)`

C

`qxx2pir^(2)`

D

`q/(r^(2))`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A circular copper ring of radius r, placed in vacuum, has charge q on it. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity of the axis of the ring at a distance x from its centres is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of E_(2) ?

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    `q/((x^(2)+r^(2))^(1//2))`
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    `q/((x^(2)+r^(2))^(3//2))`
    D
    `(qx)/((x^(2)+r^(2))^(3//2))`
  • A circular copper ring of radius r, placed in vacuum, has charge q on ti. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity of the axis of the ring at a distance x from its centres is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of x' ?

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    `sqrt(2)r`
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    `r/(sqrt(2))`
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  • A non conducting solid sphere of radius R is uniformly charged. The magnitude of electric field intensity due to the sphre at a distance r from its centre

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    increases as r increases for `r lt R`
    B
    decreases as r increases for `0 lt r lt oo`
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    decreases as r increases for `R ltr lt oo`
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    is discontinuous at `r=R`
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