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Define dielectric constant. Two charges ...

Define dielectric constant. Two charges `+-20xx10^(-6)C,` placed 2 mm apart from an electric dipole. Determine the electric field at a point 10 cm away from the centre of the dipole on its perpendicular bisector. Given, `1/(4 pi epsilon_(0))=9xx10^(9)N.m^(2).C^(-2)`

Text Solution

Verified by Experts

Ist part: NA
2nd part: Dipole moment
`p=ql=(20xx10^(-6))xx(2xx10^(-3))=4xx10^(-8)C.m 10 cm gt 2mm`, so distance of the given point is much greater than the dipole length.
`:.E=1/(4 pi epsilon_(0)) . p/(r^(3))`
`=(9xx10^(9))xx((4xx10^(-8)))/((0.1)^(3))[10cm=0.1m]`
`=3.6xx10^(5)V.m^(-1)`
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