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A Current I= I(0) e^(- lambdat) is flowi...

A Current `I= I_(0) e^(- lambdat)` is flowing in a circuit consisiting of a parallel combination of resistance R and capacitance C.
The total charge over the entire pulse period is

A

`(I_(0))/(lambda)`

B

`(2I_(0))/(lambda)`

C

`I_(0) lambda`

D

`e^(I_(0) lambda)`

Text Solution

Verified by Experts

Here, `I=I_(0) e^(- lambdat)`
The total charge ove the entire pulse period
`= int _(0) ^(oo) Idt - I_(0) int _(0)^(oo) e^(-lambda t) dt= I_(0)[ (e^(- lambda t))/(-lambda)]_(0)^(oo)=(I_(0))/(lambda)`
The option (A) is correct
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