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A positive charge Q is situated at the c...

A positive charge Q is situated at the centre of cube. The electric flux through any face of the cube is (in SI units)

A

`(Q)/(6epsi_(0))`

B

`4pi Q`

C

`(Q)/(4pi epsi_(0))`

D

`(Q)/(6 piepsi_(0))`

Text Solution

Verified by Experts

From Gauss's theorem, total flux linked with six surface of the cube is `phi`, then
`phi= int vecE* d vecS=(Q)/(epsi_(0))`
`:.` Flux linkex with any one surface `=(phi)/(6)=(Q)/(6epsi_(0))`
The option (A) is correct.
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